2sin^3x-sin^2x-sinx+1=0

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Solution for 2sin^3x-sin^2x-sinx+1=0 equation:


Simplifying
2sin3x + -1sin2x + -1sinx + 1 = 0

Reorder the terms:
1 + -1insx + -1in2sx + 2in3sx = 0

Solving
1 + -1insx + -1in2sx + 2in3sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1insx + -1in2sx + -1 + 2in3sx = 0 + -1

Reorder the terms:
1 + -1 + -1insx + -1in2sx + 2in3sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -1insx + -1in2sx + 2in3sx = 0 + -1
-1insx + -1in2sx + 2in3sx = 0 + -1

Combine like terms: 0 + -1 = -1
-1insx + -1in2sx + 2in3sx = -1

Reorder the terms:
1 + -1insx + -1in2sx + 2in3sx = -1 + 1

Combine like terms: -1 + 1 = 0
1 + -1insx + -1in2sx + 2in3sx = 0

The solution to this equation could not be determined.

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